Physics Help? Please?

Question

A liquid of density 1258 kg/m3 flows with
speed 1 m/s into a pipe of diameter 0.26 m.
The diameter of the pipe decreases to 0.05 m
at its exit end. The exit end of the pipe is
5.48 m lower than the entrance of the pipe,
and the pressure at the exit of the pipe is
1 atm.

a) What is the velocity v2 of the liquid flowing
out of the exit end of the pipe? Assume the
viscosity of the fluid is negligible and the fluid
is incompressible. The acceleration of gravity
is 9.8 m/s2 and Patm = 1.013 × 105 Pa.
Answer in units of m/s

b) Applying Bernoulli’s principle, what is the
pressure P1 at the entrance end of the pipe

I know the answer to a is 27.04 m/s i just need help on part b
Thanks in advance!

Answer 1

equate pressure head,static head and velocity head at the entry point and the exit point

your pressure head is at entry =p1/(density*acceleration due to gravity)

velocity head= (v*v)/(2*accelaration due to gravity) elevation head =5.48 at the entry and zero at the exit taking exit point as the datum you will get your answer just try